Y=-x^2+0x+16

Solution for Y=-x^2+0x+16 equation:

=-Y^2+0Y+16

We move all terms to the left:

-(-Y^2+0Y+16)=0

We get rid of parentheses

Y^2-0Y-16=0

We add all the numbers together, and all the variables

Y^2-1Y-16=0

a = 1; b = -1; c = -16;
Δ = b2-4ac
Δ = -12-4·1·(-16)
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{65}}{2*1}=\frac{1-\sqrt{65}}{2}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{65}}{2*1}=\frac{1+\sqrt{65}}{2}
$